10112009983 has 2 divisors, whose sum is σ = 10112009984. Its totient is φ = 10112009982.

The previous prime is 10112009959. The next prime is 10112010017. The reversal of 10112009983 is 38990021101.

It is an a-pointer prime, because the next prime (10112010017) can be obtained adding 10112009983 to its sum of digits (34).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10112009983 - 2¹⁷ = 10111878911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112009953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056004991 + 5056004992.

It is an arithmetic number, because the mean of its divisors is an integer number (5056004992).

Almost surely, 2^10112009983 is an apocalyptic number.

10112009983 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112009983 is an equidigital number, since it uses as much as digits as its factorization.

10112009983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 34.

The spelling of 10112009983 in words is "ten billion, one hundred twelve million, nine thousand, nine hundred eighty-three".