Base | Representation |
---|---|
bin | 11101011011100000101… |
… | …01100011001101100001 |
3 | 10120200002101222121002102 |
4 | 32231300111203031201 |
5 | 113031420203341001 |
6 | 2052312332300145 |
7 | 133025346166106 |
oct | 16556025431541 |
9 | 3520071877072 |
10 | 1011202012001 |
11 | 35a9371a0355 |
12 | 143b89611655 |
13 | 744820031cc |
14 | 36d2a0a0aad |
15 | 1b484e0ae6b |
hex | eb70563361 |
1011202012001 has 2 divisors, whose sum is σ = 1011202012002. Its totient is φ = 1011202012000.
The previous prime is 1011202011997. The next prime is 1011202012021. The reversal of 1011202012001 is 1002102021101.
1011202012001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 888869954401 + 122332057600 = 942799^2 + 349760^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011202012001 - 22 = 1011202011997 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011202012021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505601006000 + 505601006001.
It is an arithmetic number, because the mean of its divisors is an integer number (505601006001).
Almost surely, 21011202012001 is an apocalyptic number.
It is an amenable number.
1011202012001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011202012001 is an equidigital number, since it uses as much as digits as its factorization.
1011202012001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 1011202012001 its reverse (1002102021101), we get a palindrome (2013304033102).
The spelling of 1011202012001 in words is "one trillion, eleven billion, two hundred two million, twelve thousand, one".
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