101121002113 has 4 divisors (see below), whose sum is σ = 101123350020. Its totient is φ = 101118654208.

The previous prime is 101121002083. The next prime is 101121002123. The reversal of 101121002113 is 311200121101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 90418685809 + 10702316304 = 300697^2 + 103452^2 .

It is a cyclic number.

It is not a de Polignac number, because 101121002113 - 2²⁹ = 100584131201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101121002093 and 101121002102.

It is not an unprimeable number, because it can be changed into a prime (101121002123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1108120 + ... + 1195897.

It is an arithmetic number, because the mean of its divisors is an integer number (25280837505).

Almost surely, 2^101121002113 is an apocalyptic number.

It is an amenable number.

101121002113 is a deficient number, since it is larger than the sum of its proper divisors (2347907).

101121002113 is an equidigital number, since it uses as much as digits as its factorization.

101121002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2347906.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 101121002113 its reverse (311200121101), we get a palindrome (412321123214).

The spelling of 101121002113 in words is "one hundred one billion, one hundred twenty-one million, two thousand, one hundred thirteen".