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101121102101011 is a prime number
BaseRepresentation
bin10110111111100000010111…
…010111101011101000010011
3111021001002020110201002122011
4112333200113113223220103
5101223232004114213021
6555022220515323351
730204521114600206
oct2677402727535023
9437032213632564
10101121102101011
112a247244a06a73
12b411b445b0557
1344568a9a33c05
141ad8404ac993d
15ba55d2b39de1
hex5bf8175eba13

101121102101011 has 2 divisors, whose sum is σ = 101121102101012. Its totient is φ = 101121102101010.

The previous prime is 101121102100951. The next prime is 101121102101023. The reversal of 101121102101011 is 110101201121101.

It is a strong prime.

It is an emirp because it is prime and its reverse (110101201121101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101121102101011 - 219 = 101121101576723 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101121102100982 and 101121102101000.

It is not a weakly prime, because it can be changed into another prime (101121102101311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560551050505 + 50560551050506.

It is an arithmetic number, because the mean of its divisors is an integer number (50560551050506).

Almost surely, 2101121102101011 is an apocalyptic number.

101121102101011 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121102101011 is an equidigital number, since it uses as much as digits as its factorization.

101121102101011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 101121102101011 its reverse (110101201121101), we get a palindrome (211222303222112).

The spelling of 101121102101011 in words is "one hundred one trillion, one hundred twenty-one billion, one hundred two million, one hundred one thousand, eleven".