101121121 has 4 divisors (see below), whose sum is σ = 101185200. Its totient is φ = 101057044.

The previous prime is 101121109. The next prime is 101121131. The reversal of 101121121 is 121121101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121121101 = 71 ⋅1705931.

It is a cyclic number.

It is not a de Polignac number, because 101121121 - 2⁵ = 101121089 is a prime.

It is a super-2 number, since 2×101121121² = 20450962224593282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101121098 and 101121107.

It is not an unprimeable number, because it can be changed into a prime (101121131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29611 + ... + 32848.

It is an arithmetic number, because the mean of its divisors is an integer number (25296300).

Almost surely, 2^101121121 is an apocalyptic number.

It is an amenable number.

101121121 is a deficient number, since it is larger than the sum of its proper divisors (64079).

101121121 is an equidigital number, since it uses as much as digits as its factorization.

101121121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64078.

The product of its (nonzero) digits is 4, while the sum is 10.

The square root of 101121121 is about 10055.8998105590. The cubic root of 101121121 is about 465.8870353748.

Adding to 101121121 its reverse (121121101), we get a palindrome (222242222).

It can be divided in two parts, 101 and 121121, that multiplied together give a palindrome (12233221).

The spelling of 101121121 in words is "one hundred one million, one hundred twenty-one thousand, one hundred twenty-one".