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1011211341311 is a prime number
BaseRepresentation
bin11101011011100001110…
…01001000110111111111
310120200010001112120111102
432231300321020313333
5113031430100410221
62052313304243315
7133025521403213
oct16556071106777
93520101476442
101011211341311
1135a941492626
12143b9077053b
1374483c1b702
1436d2b40c943
151b485b5030b
hexeb70e48dff

1011211341311 has 2 divisors, whose sum is σ = 1011211341312. Its totient is φ = 1011211341310.

The previous prime is 1011211341233. The next prime is 1011211341353. The reversal of 1011211341311 is 1131431121101.

It is a strong prime.

It is an emirp because it is prime and its reverse (1131431121101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011211341311 - 226 = 1011144232447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011211341011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505605670655 + 505605670656.

It is an arithmetic number, because the mean of its divisors is an integer number (505605670656).

Almost surely, 21011211341311 is an apocalyptic number.

1011211341311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011211341311 is an equidigital number, since it uses as much as digits as its factorization.

1011211341311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 1011211341311 its reverse (1131431121101), we get a palindrome (2142642462412).

The spelling of 1011211341311 in words is "one trillion, eleven billion, two hundred eleven million, three hundred forty-one thousand, three hundred eleven".