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10112211223 is a prime number
BaseRepresentation
bin10010110101011110…
…00001100100010111
3222002201220112222121
421122233001210113
5131202211224343
64351231440411
7505406243242
oct113257014427
928081815877
1010112211223
11431a096a64
121b62686107
13c5201814a
146bd012259
153e2b75aed
hex25abc1917

10112211223 has 2 divisors, whose sum is σ = 10112211224. Its totient is φ = 10112211222.

The previous prime is 10112211209. The next prime is 10112211247. The reversal of 10112211223 is 32211221101.

10112211223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10112211223 - 29 = 10112210711 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112211197 and 10112211206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112211283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056105611 + 5056105612.

It is an arithmetic number, because the mean of its divisors is an integer number (5056105612).

Almost surely, 210112211223 is an apocalyptic number.

10112211223 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112211223 is an equidigital number, since it uses as much as digits as its factorization.

10112211223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10112211223 its reverse (32211221101), we get a palindrome (42323432324).

The spelling of 10112211223 in words is "ten billion, one hundred twelve million, two hundred eleven thousand, two hundred twenty-three".