10112213129 has 2 divisors, whose sum is σ = 10112213130. Its totient is φ = 10112213128.

The previous prime is 10112213101. The next prime is 10112213131. The reversal of 10112213129 is 92131221101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5205911104 + 4906302025 = 72152^2 + 70045^2 .

It is an emirp because it is prime and its reverse (92131221101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10112213129 - 2¹² = 10112209033 is a prime.

Together with 10112213131, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10112213729) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056106564 + 5056106565.

It is an arithmetic number, because the mean of its divisors is an integer number (5056106565).

Almost surely, 2^10112213129 is an apocalyptic number.

It is an amenable number.

10112213129 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112213129 is an equidigital number, since it uses as much as digits as its factorization.

10112213129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 10112213129 in words is "ten billion, one hundred twelve million, two hundred thirteen thousand, one hundred twenty-nine".