10112214113 has 8 divisors (see below), whose sum is σ = 10252534536. Its totient is φ = 9971942400.

The previous prime is 10112214107. The next prime is 10112214137. The reversal of 10112214113 is 31141221101.

It can be written as a sum of positive squares in 4 ways, for example, as 349390864 + 9762823249 = 18692^2 + 98807^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10112214113 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10112214091 and 10112214100.

It is not an unprimeable number, because it can be changed into a prime (10112214103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 661193 + ... + 676313.

It is an arithmetic number, because the mean of its divisors is an integer number (1281566817).

Almost surely, 2^10112214113 is an apocalyptic number.

It is an amenable number.

10112214113 is a deficient number, since it is larger than the sum of its proper divisors (140320423).

10112214113 is an equidigital number, since it uses as much as digits as its factorization.

10112214113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24355.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10112214113 its reverse (31141221101), we get a palindrome (41253435214).

The spelling of 10112214113 in words is "ten billion, one hundred twelve million, two hundred fourteen thousand, one hundred thirteen".