1011222001241 has 4 divisors (see below), whose sum is σ = 1055188175232. Its totient is φ = 967255827252.

The previous prime is 1011222001189. The next prime is 1011222001327. The reversal of 1011222001241 is 1421002221101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011222001241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1011222001841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21983086961 + ... + 21983087006.

It is an arithmetic number, because the mean of its divisors is an integer number (263797043808).

Almost surely, 2^{1011222001241} is an apocalyptic number.

It is an amenable number.

1011222001241 is a deficient number, since it is larger than the sum of its proper divisors (43966173991).

1011222001241 is an equidigital number, since it uses as much as digits as its factorization.

1011222001241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43966173990.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 1011222001241 its reverse (1421002221101), we get a palindrome (2432224222342).

The spelling of 1011222001241 in words is "one trillion, eleven billion, two hundred twenty-two million, one thousand, two hundred forty-one".