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1011222031312 = 2463201376957
BaseRepresentation
bin11101011011100011000…
…01111010101111010000
310120200010210122200102101
432231301201322233100
5113031440320000222
62052314325330144
7133026011305333
oct16556141725720
93520123580371
101011222031312
1135a947524139
12143b94266954
13744861c235c
1436d2c9d261a
151b486a62927
hexeb7187abd0

1011222031312 has 10 divisors (see below), whose sum is σ = 1959242685698. Its totient is φ = 505611015648.

The previous prime is 1011222031297. The next prime is 1011222031321. The reversal of 1011222031312 is 2131302221101.

It can be written as a sum of positive squares in only one way, i.e., 815907532176 + 195314499136 = 903276^2 + 441944^2 .

It is a super-2 number, since 2×10112220313122 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1011222031312.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31600688463 + ... + 31600688494.

Almost surely, 21011222031312 is an apocalyptic number.

It is an amenable number.

1011222031312 is a deficient number, since it is larger than the sum of its proper divisors (948020654386).

1011222031312 is an equidigital number, since it uses as much as digits as its factorization.

1011222031312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63201376965 (or 63201376959 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1011222031312 its reverse (2131302221101), we get a palindrome (3142524252413).

The spelling of 1011222031312 in words is "one trillion, eleven billion, two hundred twenty-two million, thirty-one thousand, three hundred twelve".

Divisors: 1 2 4 8 16 63201376957 126402753914 252805507828 505611015656 1011222031312