Base | Representation |
---|---|
bin | 101111000101101011… |
… | …1000000010010010111 |
3 | 100200000101110122221121 |
4 | 1132023113000102113 |
5 | 3124044302430234 |
6 | 114242134024411 |
7 | 10206622315111 |
oct | 1361327002227 |
9 | 320011418847 |
10 | 101122311319 |
11 | 399819aa217 |
12 | 177217a8107 |
13 | 96c71a2893 |
14 | 4c7412a3b1 |
15 | 296ca2b4b4 |
hex | 178b5c0497 |
101122311319 has 2 divisors, whose sum is σ = 101122311320. Its totient is φ = 101122311318.
The previous prime is 101122311281. The next prime is 101122311341. The reversal of 101122311319 is 913113221101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101122311319 - 223 = 101113922711 is a prime.
It is a super-3 number, since 3×1011223113193 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 101122311293 and 101122311302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101122311919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561155659 + 50561155660.
It is an arithmetic number, because the mean of its divisors is an integer number (50561155660).
Almost surely, 2101122311319 is an apocalyptic number.
101122311319 is a deficient number, since it is larger than the sum of its proper divisors (1).
101122311319 is an equidigital number, since it uses as much as digits as its factorization.
101122311319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 101122311319 in words is "one hundred one billion, one hundred twenty-two million, three hundred eleven thousand, three hundred nineteen".
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