Base | Representation |
---|---|
bin | 10010110101011110… |
… | …11001111111001001 |
3 | 222002202002122011222 |
4 | 21122233121333021 |
5 | 131202222424431 |
6 | 4351233531425 |
7 | 505410140654 |
oct | 113257317711 |
9 | 28082078158 |
10 | 10112311241 |
11 | 431a15511a |
12 | 1b62713b75 |
13 | c52051826 |
14 | 6bd03a89b |
15 | 3e2b9557b |
hex | 25abd9fc9 |
10112311241 has 2 divisors, whose sum is σ = 10112311242. Its totient is φ = 10112311240.
The previous prime is 10112311211. The next prime is 10112311243. The reversal of 10112311241 is 14211321101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5355312400 + 4756998841 = 73180^2 + 68971^2 .
It is a cyclic number.
It is not a de Polignac number, because 10112311241 - 26 = 10112311177 is a prime.
Together with 10112311243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10112311243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056155620 + 5056155621.
It is an arithmetic number, because the mean of its divisors is an integer number (5056155621).
Almost surely, 210112311241 is an apocalyptic number.
It is an amenable number.
10112311241 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112311241 is an equidigital number, since it uses as much as digits as its factorization.
10112311241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 10112311241 its reverse (14211321101), we get a palindrome (24323632342).
The spelling of 10112311241 in words is "ten billion, one hundred twelve million, three hundred eleven thousand, two hundred forty-one".
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