10112322113 has 4 divisors (see below), whose sum is σ = 10116589488. Its totient is φ = 10108054740.

The previous prime is 10112322091. The next prime is 10112322119. The reversal of 10112322113 is 31122321101.

10112322113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10112322113 - 2⁶ = 10112322049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10112322091 and 10112322100.

It is not an unprimeable number, because it can be changed into a prime (10112322119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2130131 + ... + 2134872.

It is an arithmetic number, because the mean of its divisors is an integer number (2529147372).

Almost surely, 2^10112322113 is an apocalyptic number.

It is an amenable number.

10112322113 is a deficient number, since it is larger than the sum of its proper divisors (4267375).

10112322113 is an equidigital number, since it uses as much as digits as its factorization.

10112322113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4267374.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10112322113 its reverse (31122321101), we get a palindrome (41234643214).

The spelling of 10112322113 in words is "ten billion, one hundred twelve million, three hundred twenty-two thousand, one hundred thirteen".