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1011244352213 is a prime number
BaseRepresentation
bin11101011011100101101…
…11000100001011010101
310120200012100122200221102
432231302313010023111
5113032012023232323
62052320443555445
7133026402112004
oct16556267041325
93520170580842
101011244352213
1135a95908a167
12143b9b82bb85
137448aa08ca4
1436d31962c3b
151b4889c1328
hexeb72dc42d5

1011244352213 has 2 divisors, whose sum is σ = 1011244352214. Its totient is φ = 1011244352212.

The previous prime is 1011244352191. The next prime is 1011244352233. The reversal of 1011244352213 is 3122534421101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 720721196209 + 290523156004 = 848953^2 + 539002^2 .

It is an emirp because it is prime and its reverse (3122534421101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011244352213 - 222 = 1011240157909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011244352233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505622176106 + 505622176107.

It is an arithmetic number, because the mean of its divisors is an integer number (505622176107).

Almost surely, 21011244352213 is an apocalyptic number.

It is an amenable number.

1011244352213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011244352213 is an equidigital number, since it uses as much as digits as its factorization.

1011244352213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 1011244352213 its reverse (3122534421101), we get a palindrome (4133778773314).

The spelling of 1011244352213 in words is "one trillion, eleven billion, two hundred forty-four million, three hundred fifty-two thousand, two hundred thirteen".