101130000131 has 4 divisors (see below), whose sum is σ = 101133090072. Its totient is φ = 101126910192.

The previous prime is 101130000119. The next prime is 101130000173. The reversal of 101130000131 is 131000031101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131000031101 = 19 ⋅6894738479.

It is a cyclic number.

It is not a de Polignac number, because 101130000131 - 2¹⁰ = 101129999107 is a prime.

It is a super-2 number, since 2×101130000131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101130000431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1495346 + ... + 1561511.

It is an arithmetic number, because the mean of its divisors is an integer number (25283272518).

Almost surely, 2^101130000131 is an apocalyptic number.

101130000131 is a deficient number, since it is larger than the sum of its proper divisors (3089941).

101130000131 is an equidigital number, since it uses as much as digits as its factorization.

101130000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3089940.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 101130000131 its reverse (131000031101), we get a palindrome (232130031232).

The spelling of 101130000131 in words is "one hundred one billion, one hundred thirty million, one hundred thirty-one", and thus it is an aban number.