Base | Representation |
---|---|
bin | 10010110101100100… |
… | …00010001001111111 |
3 | 222002210101122001220 |
4 | 21122302002021333 |
5 | 131202412000223 |
6 | 4351300404423 |
7 | 505416040125 |
oct | 113262021177 |
9 | 28083348056 |
10 | 10113000063 |
11 | 431a5856a1 |
12 | 1b629a6713 |
13 | c5223320a |
14 | 6bd179915 |
15 | 3e2c7e6e3 |
hex | 25ac8227f |
10113000063 has 4 divisors (see below), whose sum is σ = 13484000088. Its totient is φ = 6742000040.
The previous prime is 10113000049. The next prime is 10113000067. The reversal of 10113000063 is 36000031101.
10113000063 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10113000063 - 217 = 10112868991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10113000067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685500008 + ... + 1685500013.
It is an arithmetic number, because the mean of its divisors is an integer number (3371000022).
Almost surely, 210113000063 is an apocalyptic number.
10113000063 is a deficient number, since it is larger than the sum of its proper divisors (3371000025).
10113000063 is an equidigital number, since it uses as much as digits as its factorization.
10113000063 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3371000024.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10113000063 its reverse (36000031101), we get a palindrome (46113031164).
The spelling of 10113000063 in words is "ten billion, one hundred thirteen million, sixty-three", and thus it is an aban number.
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