101130001120133 has 4 divisors (see below), whose sum is σ = 101130033357600. Its totient is φ = 101129968882668.

The previous prime is 101130001120123. The next prime is 101130001120207. The reversal of 101130001120133 is 331021100031101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101130001120133 - 2²⁶ = 101129934011269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101130001120123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10836083 + ... + 17879616.

It is an arithmetic number, because the mean of its divisors is an integer number (25282508339400).

Almost surely, 2^{101130001120133} is an apocalyptic number.

It is an amenable number.

101130001120133 is a deficient number, since it is larger than the sum of its proper divisors (32237467).

101130001120133 is an equidigital number, since it uses as much as digits as its factorization.

101130001120133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32237466.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101130001120133 its reverse (331021100031101), we get a palindrome (432151101151234).

The spelling of 101130001120133 in words is "one hundred one trillion, one hundred thirty billion, one million, one hundred twenty thousand, one hundred thirty-three".