Base | Representation |
---|---|
bin | 10010110101100100… |
… | …00010111010000111 |
3 | 222002210101210021222 |
4 | 21122302002322013 |
5 | 131202412100033 |
6 | 4351300430555 |
7 | 505416052115 |
oct | 113262027207 |
9 | 28083353258 |
10 | 10113003143 |
11 | 431a587a41 |
12 | 1b629a845b |
13 | c52234739 |
14 | 6bd17aab5 |
15 | 3e2c80598 |
hex | 25ac82e87 |
10113003143 has 2 divisors, whose sum is σ = 10113003144. Its totient is φ = 10113003142.
The previous prime is 10113003127. The next prime is 10113003149. The reversal of 10113003143 is 34130031101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10113003143 - 24 = 10113003127 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10113003149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056501571 + 5056501572.
It is an arithmetic number, because the mean of its divisors is an integer number (5056501572).
Almost surely, 210113003143 is an apocalyptic number.
10113003143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113003143 is an equidigital number, since it uses as much as digits as its factorization.
10113003143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 10113003143 its reverse (34130031101), we get a palindrome (44243034244).
The spelling of 10113003143 in words is "ten billion, one hundred thirteen million, three thousand, one hundred forty-three".
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