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101130032031000 = 23353710944180879
BaseRepresentation
bin10110111111101000101011…
…101000101010010100011000
3111021001221021210221112122220
4112333220223220222110120
5101223403301144443000
6555030254554544040
730205255320003420
oct2677505350522430
9437057253845586
10101130032031000
112a2500076995a5
12b413817138020
1344576a0b1c85b
141ad8a10aa1480
15ba5956ac51a0
hex5bfa2ba2a518

101130032031000 has 256 divisors, whose sum is σ = 363909072384000. Its totient is φ = 22903367155200.

The previous prime is 101130032030999. The next prime is 101130032031079. The reversal of 101130032031000 is 130230031101.

It is a super-2 number, since 2×1011300320310002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19801440 + ... + 24379439.

It is an arithmetic number, because the mean of its divisors is an integer number (1421519814000).

Almost surely, 2101130032031000 is an apocalyptic number.

101130032031000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

101130032031000 is an abundant number, since it is smaller than the sum of its proper divisors (262779040353000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101130032031000 is a wasteful number, since it uses less digits than its factorization.

101130032031000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44181019 (or 44181005 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 101130032031000 its reverse (130230031101), we get a palindrome (101260262062101).

The spelling of 101130032031000 in words is "one hundred one trillion, one hundred thirty billion, thirty-two million, thirty-one thousand".