Base | Representation |
---|---|
bin | 1100000011100… |
… | …01111101000101 |
3 | 21001021221100112 |
4 | 12001301331011 |
5 | 201342130203 |
6 | 14011322405 |
7 | 2335406543 |
oct | 601617505 |
9 | 231257315 |
10 | 101130053 |
11 | 520a3562 |
12 | 29a50405 |
13 | 17c4ac8b |
14 | d606d93 |
15 | 8d296d8 |
hex | 6071f45 |
101130053 has 2 divisors, whose sum is σ = 101130054. Its totient is φ = 101130052.
The previous prime is 101130049. The next prime is 101130101. The reversal of 101130053 is 350031101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99062209 + 2067844 = 9953^2 + 1438^2 .
It is a cyclic number.
It is not a de Polignac number, because 101130053 - 22 = 101130049 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101130353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565026 + 50565027.
It is an arithmetic number, because the mean of its divisors is an integer number (50565027).
Almost surely, 2101130053 is an apocalyptic number.
It is an amenable number.
101130053 is a deficient number, since it is larger than the sum of its proper divisors (1).
101130053 is an equidigital number, since it uses as much as digits as its factorization.
101130053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45, while the sum is 14.
The square root of 101130053 is about 10056.3439181444. The cubic root of 101130053 is about 465.9007521943.
Adding to 101130053 its reverse (350031101), we get a palindrome (451161154).
The spelling of 101130053 in words is "one hundred one million, one hundred thirty thousand, fifty-three".
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