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10113022243303 = 72564136587167
BaseRepresentation
bin1001001100101001111100…
…0110010011000111100111
31022210210110220112002121121
42103022133012103013213
52311142432143241203
633301505215554411
72062433055511600
oct223123706230747
938723426462547
1010113022243303
1132499aa457271
121173b7a82ba07
13584866827175
1426d689868da7
151280e25250bd
hex9329f1931e7

10113022243303 has 12 divisors (see below), whose sum is σ = 11766213705792. Its totient is φ = 8666767882080.

The previous prime is 10113022243283. The next prime is 10113022243339. The reversal of 10113022243303 is 30334222031101.

It is not a de Polignac number, because 10113022243303 - 217 = 10113022112231 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113022243393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18017175 + ... + 18569992.

It is an arithmetic number, because the mean of its divisors is an integer number (980517808816).

Almost surely, 210113022243303 is an apocalyptic number.

10113022243303 is a deficient number, since it is larger than the sum of its proper divisors (1653191462489).

10113022243303 is an equidigital number, since it uses as much as digits as its factorization.

10113022243303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36592822 (or 36592815 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10113022243303 its reverse (30334222031101), we get a palindrome (40447244274404).

The spelling of 10113022243303 in words is "ten trillion, one hundred thirteen billion, twenty-two million, two hundred forty-three thousand, three hundred three".

Divisors: 1 7 49 5641 39487 276409 36587167 256110169 1792771183 206388209047 1444717463329 10113022243303