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101131001210112 = 283375382781197
BaseRepresentation
bin10110111111101001100101…
…011001110010010100000000
3111021002000210100121221110120
4112333221211121302110000
5101223412242302210422
6555030535055500240
730205321325616456
oct2677514531622400
9437060710557416
10101131001210112
112a250464781175
12b413a47827680
1344577c6858213
141ad8aa36a89d6
15ba59b1c1945c
hex5bfa65672500

101131001210112 has 288 divisors, whose sum is σ = 281990135935872. Its totient is φ = 32141081935872.

The previous prime is 101131001210101. The next prime is 101131001210167. The reversal of 101131001210112 is 211012100131101.

It is a junction number, because it is equal to n+sod(n) for n = 101131001210091 and 101131001210100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1245461098 + ... + 1245542294.

It is an arithmetic number, because the mean of its divisors is an integer number (979132416444).

Almost surely, 2101131001210112 is an apocalyptic number.

101131001210112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101131001210112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (140995067967936).

101131001210112 is an abundant number, since it is smaller than the sum of its proper divisors (180859134725760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101131001210112 is an equidigital number, since it uses as much as digits as its factorization.

101131001210112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82133 (or 82119 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 101131001210112 its reverse (211012100131101), we get a palindrome (312143101341213).

The spelling of 101131001210112 in words is "one hundred one trillion, one hundred thirty-one billion, one million, two hundred ten thousand, one hundred twelve".