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10113103015 = 52022620603
BaseRepresentation
bin10010110101100100…
…11011010010100111
3222002210120212021221
421122302123102213
5131202423244030
64351302521211
7505416646231
oct113262332247
928083525257
1010113103015
11431a645a84
121b62a36207
13c5226b032
146bd1a5251
153e2c9ee7a
hex25ac9b4a7

10113103015 has 4 divisors (see below), whose sum is σ = 12135723624. Its totient is φ = 8090482408.

The previous prime is 10113102947. The next prime is 10113103069. The reversal of 10113103015 is 51030131101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51030131101 = 85959406439.

It is a cyclic number.

It is not a de Polignac number, because 10113103015 - 231 = 7965619367 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10113103015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1011310297 + ... + 1011310306.

It is an arithmetic number, because the mean of its divisors is an integer number (3033930906).

Almost surely, 210113103015 is an apocalyptic number.

10113103015 is a deficient number, since it is larger than the sum of its proper divisors (2022620609).

10113103015 is an equidigital number, since it uses as much as digits as its factorization.

10113103015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2022620608.

The product of its (nonzero) digits is 45, while the sum is 16.

Adding to 10113103015 its reverse (51030131101), we get a palindrome (61143234116).

The spelling of 10113103015 in words is "ten billion, one hundred thirteen million, one hundred three thousand, fifteen".

Divisors: 1 5 2022620603 10113103015