10113110323 has 2 divisors, whose sum is σ = 10113110324. Its totient is φ = 10113110322.

The previous prime is 10113110321. The next prime is 10113110341. The reversal of 10113110323 is 32301131101.

10113110323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10113110323 - 2¹ = 10113110321 is a prime.

Together with 10113110321, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10113110297 and 10113110306.

It is not a weakly prime, because it can be changed into another prime (10113110321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056555161 + 5056555162.

It is an arithmetic number, because the mean of its divisors is an integer number (5056555162).

Almost surely, 2^10113110323 is an apocalyptic number.

10113110323 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113110323 is an equidigital number, since it uses as much as digits as its factorization.

10113110323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10113110323 its reverse (32301131101), we get a palindrome (42414241424).

The spelling of 10113110323 in words is "ten billion, one hundred thirteen million, one hundred ten thousand, three hundred twenty-three".