10113113041 has 4 divisors (see below), whose sum is σ = 10552813632. Its totient is φ = 9673412452.

The previous prime is 10113113027. The next prime is 10113113047. The reversal of 10113113041 is 14031131101.

10113113041 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10113113041 - 2²³ = 10104724433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10113113047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219850261 + ... + 219850306.

It is an arithmetic number, because the mean of its divisors is an integer number (2638203408).

Almost surely, 2^10113113041 is an apocalyptic number.

It is an amenable number.

10113113041 is a deficient number, since it is larger than the sum of its proper divisors (439700591).

10113113041 is an equidigital number, since it uses as much as digits as its factorization.

10113113041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 439700590.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 10113113041 its reverse (14031131101), we get a palindrome (24144244142).

The spelling of 10113113041 in words is "ten billion, one hundred thirteen million, one hundred thirteen thousand, forty-one".