Base | Representation |
---|---|
bin | 1001001100101010010011… |
… | …1011010010101011010011 |
3 | 1022210210201201111201200022 |
4 | 2103022210323102223103 |
5 | 2311143132211134303 |
6 | 33301523031414055 |
7 | 2062435353560423 |
oct | 223124473225323 |
9 | 38723651451608 |
10 | 10113120021203 |
11 | 3249a4a670251 |
12 | 1173ba752432b |
13 | 584880b70404 |
14 | 26d69883c483 |
15 | 1280eaddb438 |
hex | 932a4ed2ad3 |
10113120021203 has 2 divisors, whose sum is σ = 10113120021204. Its totient is φ = 10113120021202.
The previous prime is 10113120021149. The next prime is 10113120021211. The reversal of 10113120021203 is 30212002131101.
10113120021203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10113120021203 - 224 = 10113103243987 is a prime.
It is not a weakly prime, because it can be changed into another prime (10113170021203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056560010601 + 5056560010602.
It is an arithmetic number, because the mean of its divisors is an integer number (5056560010602).
Almost surely, 210113120021203 is an apocalyptic number.
10113120021203 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113120021203 is an equidigital number, since it uses as much as digits as its factorization.
10113120021203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 10113120021203 its reverse (30212002131101), we get a palindrome (40325122152304).
The spelling of 10113120021203 in words is "ten trillion, one hundred thirteen billion, one hundred twenty million, twenty-one thousand, two hundred three".
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