10113131130113 has 4 divisors (see below), whose sum is σ = 11032506687408. Its totient is φ = 9193755572820.

The previous prime is 10113131130103. The next prime is 10113131130131. The reversal of 10113131130113 is 31103113131101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10113131130113 - 2²² = 10113126935809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10113131130103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 459687778631 + ... + 459687778652.

It is an arithmetic number, because the mean of its divisors is an integer number (2758126671852).

Almost surely, 2^{10113131130113} is an apocalyptic number.

It is an amenable number.

10113131130113 is a deficient number, since it is larger than the sum of its proper divisors (919375557295).

10113131130113 is an equidigital number, since it uses as much as digits as its factorization.

10113131130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 919375557294.

The product of its (nonzero) digits is 81, while the sum is 20.

Adding to 10113131130113 its reverse (31103113131101), we get a palindrome (41216244261214).

The spelling of 10113131130113 in words is "ten trillion, one hundred thirteen billion, one hundred thirty-one million, one hundred thirty thousand, one hundred thirteen".