10113210000301 has 2 divisors, whose sum is σ = 10113210000302. Its totient is φ = 10113210000300.

The previous prime is 10113210000281. The next prime is 10113210000319. The reversal of 10113210000301 is 10300001231101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6491233884100 + 3621976116201 = 2547790^2 + 1903149^2 .

It is a cyclic number.

It is not a de Polignac number, because 10113210000301 - 2²⁹ = 10112673129389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10113210000331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056605000150 + 5056605000151.

It is an arithmetic number, because the mean of its divisors is an integer number (5056605000151).

Almost surely, 2^{10113210000301} is an apocalyptic number.

It is an amenable number.

10113210000301 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113210000301 is an equidigital number, since it uses as much as digits as its factorization.

10113210000301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10113210000301 its reverse (10300001231101), we get a palindrome (20413211231402).

The spelling of 10113210000301 in words is "ten trillion, one hundred thirteen billion, two hundred ten million, three hundred one", and thus it is an aban number.