Base | Representation |
---|---|
bin | 10010110101100101… |
… | …10101101011110011 |
3 | 222002210210100120221 |
4 | 21122302311223303 |
5 | 131202440223443 |
6 | 4351305113511 |
7 | 505420606351 |
oct | 113262655363 |
9 | 28083710527 |
10 | 10113211123 |
11 | 431a70a224 |
12 | 1b62a88897 |
13 | c522a82c2 |
14 | 6bd1d27d1 |
15 | 3e2cc1eed |
hex | 25acb5af3 |
10113211123 has 2 divisors, whose sum is σ = 10113211124. Its totient is φ = 10113211122.
The previous prime is 10113211099. The next prime is 10113211139. The reversal of 10113211123 is 32111231101.
It is a happy number.
It is an a-pointer prime, because the next prime (10113211139) can be obtained adding 10113211123 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10113211123 is a prime.
It is a super-2 number, since 2×101132111232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10113211097 and 10113211106.
It is not a weakly prime, because it can be changed into another prime (10113211723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056605561 + 5056605562.
It is an arithmetic number, because the mean of its divisors is an integer number (5056605562).
Almost surely, 210113211123 is an apocalyptic number.
10113211123 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113211123 is an equidigital number, since it uses as much as digits as its factorization.
10113211123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 10113211123 its reverse (32111231101), we get a palindrome (42224442224).
The spelling of 10113211123 in words is "ten billion, one hundred thirteen million, two hundred eleven thousand, one hundred twenty-three".
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