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101132111322000 = 243253113713804547
BaseRepresentation
bin10110111111101010100111…
…100100100001101110010000
3111021002010122201111110200200
4112333222213210201232100
5101223422030444301000
6555031241153215200
730205360665456333
oct2677524744415620
9437063581443620
10101132111322000
112a250984372710
12b4140b7561500
134457942839665
141ad8b6acba61a
15ba5a293eb500
hex5bfaa7921b90

101132111322000 has 480 divisors, whose sum is σ = 395746131590784. Its totient is φ = 23854255488000.

The previous prime is 101132111321959. The next prime is 101132111322001. The reversal of 101132111322000 is 223111231101.

101132111322000 is a `hidden beast` number, since 1 + 0 + 11 + 321 + 1 + 132 + 200 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (101132111322001) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 423727 + ... + 14228273.

Almost surely, 2101132111322000 is an apocalyptic number.

101132111322000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101132111322000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (197873065795392).

101132111322000 is an abundant number, since it is smaller than the sum of its proper divisors (294614020268784).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101132111322000 is a wasteful number, since it uses less digits than its factorization.

101132111322000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13804624 (or 13804605 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 101132111322000 its reverse (223111231101), we get a palindrome (101355222553101).

It can be divided in two parts, 1011321 and 11322000, that added together give a palindrome (12333321).

The spelling of 101132111322000 in words is "one hundred one trillion, one hundred thirty-two billion, one hundred eleven million, three hundred twenty-two thousand".