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10113230005 = 58272445763
BaseRepresentation
bin10010110101100101…
…11010010010110101
3222002210211022111021
421122302322102311
5131202441330010
64351305341141
7505421015404
oct113262722265
928083738437
1010113230005
11431a72242a
121b62a977b1
13c522b3a88
146bd1d963b
153e2cc78da
hex25acba4b5

10113230005 has 8 divisors (see below), whose sum is σ = 12150555552. Its totient is φ = 8080797648.

The previous prime is 10113229993. The next prime is 10113230009. The reversal of 10113230005 is 50003231101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10113230005 - 213 = 10113221813 is a prime.

It is a super-2 number, since 2×101132300052 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113230009) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1218747 + ... + 1227016.

It is an arithmetic number, because the mean of its divisors is an integer number (1518819444).

Almost surely, 210113230005 is an apocalyptic number.

It is an amenable number.

10113230005 is a deficient number, since it is larger than the sum of its proper divisors (2037325547).

10113230005 is an equidigital number, since it uses as much as digits as its factorization.

10113230005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2446595.

The product of its (nonzero) digits is 90, while the sum is 16.

Adding to 10113230005 its reverse (50003231101), we get a palindrome (60116461106).

The spelling of 10113230005 in words is "ten billion, one hundred thirteen million, two hundred thirty thousand, five".

Divisors: 1 5 827 4135 2445763 12228815 2022646001 10113230005