1011330001 has 4 divisors (see below), whose sum is σ = 1103269104. Its totient is φ = 919390900.

The previous prime is 1011329993. The next prime is 1011330053. The reversal of 1011330001 is 1000331101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1011330001 - 2³ = 1011329993 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1011330001.

It is not an unprimeable number, because it can be changed into a prime (1011337001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45969535 + ... + 45969556.

It is an arithmetic number, because the mean of its divisors is an integer number (275817276).

Almost surely, 2^1011330001 is an apocalyptic number.

1011330001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1011330001 is a deficient number, since it is larger than the sum of its proper divisors (91939103).

1011330001 is an equidigital number, since it uses as much as digits as its factorization.

1011330001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91939102.

The product of its (nonzero) digits is 9, while the sum is 10.

The square root of 1011330001 is about 31801.4150785779. The cubic root of 1011330001 is about 1003.7624928928.

Adding to 1011330001 its reverse (1000331101), we get a palindrome (2011661102).

The spelling of 1011330001 in words is "one billion, eleven million, three hundred thirty thousand, one".