101133112111 has 4 divisors (see below), whose sum is σ = 103599773424. Its totient is φ = 98666450800.

The previous prime is 101133112079. The next prime is 101133112127. The reversal of 101133112111 is 111211331101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 101133112111 - 2⁵ = 101133112079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101133112141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1233330595 + ... + 1233330676.

It is an arithmetic number, because the mean of its divisors is an integer number (25899943356).

Almost surely, 2^101133112111 is an apocalyptic number.

101133112111 is a deficient number, since it is larger than the sum of its proper divisors (2466661313).

101133112111 is an equidigital number, since it uses as much as digits as its factorization.

101133112111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2466661312.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 101133112111 its reverse (111211331101), we get a palindrome (212344443212).

The spelling of 101133112111 in words is "one hundred one billion, one hundred thirty-three million, one hundred twelve thousand, one hundred eleven".