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10113433 = 111019103
BaseRepresentation
bin100110100101…
…000110011001
3201000211000121
4212211012121
510042112213
61000433241
7151651141
oct46450631
921024017
1010113433
115788410
123478821
1321313a5
1414b3921
15d4b88d
hex9a5199

10113433 has 8 divisors (see below), whose sum is σ = 11143296. Its totient is φ = 9102000.

The previous prime is 10113401. The next prime is 10113437. The reversal of 10113433 is 33431101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10113433 - 25 = 10113401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10113437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3441 + ... + 5662.

It is an arithmetic number, because the mean of its divisors is an integer number (1392912).

Almost surely, 210113433 is an apocalyptic number.

It is an amenable number.

10113433 is a deficient number, since it is larger than the sum of its proper divisors (1029863).

10113433 is a wasteful number, since it uses less digits than its factorization.

10113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9215.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 10113433 is about 3180.1624172359. The cubic root of 10113433 is about 216.2550214344.

Adding to 10113433 its reverse (33431101), we get a palindrome (43544534).

It can be divided in two parts, 1011 and 3433, that added together give a palindrome (4444).

The spelling of 10113433 in words is "ten million, one hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 11 101 1111 9103 100133 919403 10113433