10113525504307 has 2 divisors, whose sum is σ = 10113525504308. Its totient is φ = 10113525504306.

The previous prime is 10113525504241. The next prime is 10113525504373. The reversal of 10113525504307 is 70340552531101.

It is a balanced prime because it is at equal distance from previous prime (10113525504241) and next prime (10113525504373).

It is a cyclic number.

It is not a de Polignac number, because 10113525504307 - 2¹⁹ = 10113524980019 is a prime.

It is a super-3 number, since 3×10113525504307³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10113525804307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056762752153 + 5056762752154.

It is an arithmetic number, because the mean of its divisors is an integer number (5056762752154).

Almost surely, 2^{10113525504307} is an apocalyptic number.

10113525504307 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113525504307 is an equidigital number, since it uses as much as digits as its factorization.

10113525504307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63000, while the sum is 37.

The spelling of 10113525504307 in words is "ten trillion, one hundred thirteen billion, five hundred twenty-five million, five hundred four thousand, three hundred seven".