10113525504373 has 2 divisors, whose sum is σ = 10113525504374. Its totient is φ = 10113525504372.

The previous prime is 10113525504307. The next prime is 10113525504409. The reversal of 10113525504373 is 37340552531101.

10113525504373 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9547747743249 + 565777761124 = 3089943^2 + 752182^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10113525504373 is a prime.

It is a super-3 number, since 3×10113525504373³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10113525904373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056762752186 + 5056762752187.

It is an arithmetic number, because the mean of its divisors is an integer number (5056762752187).

Almost surely, 2^{10113525504373} is an apocalyptic number.

It is an amenable number.

10113525504373 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113525504373 is an equidigital number, since it uses as much as digits as its factorization.

10113525504373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 189000, while the sum is 40.

The spelling of 10113525504373 in words is "ten trillion, one hundred thirteen billion, five hundred twenty-five million, five hundred four thousand, three hundred seventy-three".