Base | Representation |
---|---|
bin | 10010110101101000… |
… | …00110110010100111 |
3 | 222002211102020022002 |
4 | 21122310012302213 |
5 | 131203031341320 |
6 | 4351320155515 |
7 | 505423462040 |
oct | 113264066247 |
9 | 28084366262 |
10 | 10113543335 |
11 | 431a916885 |
12 | 1b63008b9b |
13 | c5239358c |
14 | 6bd27b8c7 |
15 | 3e2d3a675 |
hex | 25ad06ca7 |
10113543335 has 32 divisors (see below), whose sum is σ = 13965460992. Its totient is φ = 6887422080.
The previous prime is 10113543299. The next prime is 10113543337. The reversal of 10113543335 is 53334531101.
10113543335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10113543335 - 220 = 10112494759 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10113543298 and 10113543307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10113543337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4333829 + ... + 4336161.
It is an arithmetic number, because the mean of its divisors is an integer number (436420656).
Almost surely, 210113543335 is an apocalyptic number.
10113543335 is a deficient number, since it is larger than the sum of its proper divisors (3851917657).
10113543335 is a wasteful number, since it uses less digits than its factorization.
10113543335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3143.
The product of its (nonzero) digits is 8100, while the sum is 29.
The spelling of 10113543335 in words is "ten billion, one hundred thirteen million, five hundred forty-three thousand, three hundred thirty-five".
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