Base | Representation |
---|---|
bin | 101111000110001101… |
… | …1110001111101001001 |
3 | 100200001122101122102000 |
4 | 1132030123301331021 |
5 | 3124113411344203 |
6 | 114244020301213 |
7 | 10210231465350 |
oct | 1361433617511 |
9 | 320048348360 |
10 | 101140340553 |
11 | 399910a390a |
12 | 17727841809 |
13 | 96cab45c75 |
14 | 4c766a0997 |
15 | 296e3dd4a3 |
hex | 178c6f1f49 |
101140340553 has 64 divisors (see below), whose sum is σ = 179177963520. Its totient is φ = 55130175936.
The previous prime is 101140340537. The next prime is 101140340563. The reversal of 101140340553 is 355043041101.
It is a happy number.
101140340553 is a `hidden beast` number, since 101 + 1 + 4 + 0 + 3 + 4 + 0 + 553 = 666.
It is not a de Polignac number, because 101140340553 - 24 = 101140340537 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (101140340503) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1563651 + ... + 1627047.
It is an arithmetic number, because the mean of its divisors is an integer number (2799655680).
Almost surely, 2101140340553 is an apocalyptic number.
It is an amenable number.
101140340553 is a deficient number, since it is larger than the sum of its proper divisors (78037622967).
101140340553 is a wasteful number, since it uses less digits than its factorization.
101140340553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63803 (or 63797 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 101140340553 its reverse (355043041101), we get a palindrome (456183381654).
The spelling of 101140340553 in words is "one hundred one billion, one hundred forty million, three hundred forty thousand, five hundred fifty-three".
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