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10114040143135 = 517203117584609
BaseRepresentation
bin1001001100101101101111…
…0001010001110100011111
31022210220002211212202200101
42103023123301101310133
52311202023234040020
633302154221041531
72062500225513565
oct223133361216437
938726084782611
1010114040143135
11324a381a964a5
1211742036b62a7
13584999690866
1426d744b15a35
15128151a9000a
hex932dbc51d1f

10114040143135 has 8 divisors (see below), whose sum is σ = 12137553782640. Its totient is φ = 8090761707264.

The previous prime is 10114040143121. The next prime is 10114040143139. The reversal of 10114040143135 is 53134104041101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10114040143135 - 213 = 10114040134943 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10114040143139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58706290 + ... + 58878319.

It is an arithmetic number, because the mean of its divisors is an integer number (1517194222830).

Almost surely, 210114040143135 is an apocalyptic number.

10114040143135 is a deficient number, since it is larger than the sum of its proper divisors (2023513639505).

10114040143135 is a wasteful number, since it uses less digits than its factorization.

10114040143135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117601817.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 10114040143135 its reverse (53134104041101), we get a palindrome (63248144184236).

The spelling of 10114040143135 in words is "ten trillion, one hundred fourteen billion, forty million, one hundred forty-three thousand, one hundred thirty-five".

Divisors: 1 5 17203 86015 117584609 587923045 2022808028627 10114040143135