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10114103141 = 27947361903
BaseRepresentation
bin10010110101101100…
…01111011101100101
3222002212110200012122
421122312033131211
5131203202300031
64351340155325
7505431313112
oct113266173545
928085420178
1010114103141
11432016942a
121b63238b45
13c5252b31c
146bd385909
153e2deb47b
hex25ad8f765

10114103141 has 4 divisors (see below), whose sum is σ = 10114492992. Its totient is φ = 10113713292.

The previous prime is 10114103137. The next prime is 10114103221. The reversal of 10114103141 is 14130141101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14130141101 = 15299923599.

It is a cyclic number.

It is not a de Polignac number, because 10114103141 - 22 = 10114103137 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10114106141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153005 + ... + 208898.

It is an arithmetic number, because the mean of its divisors is an integer number (2528623248).

Almost surely, 210114103141 is an apocalyptic number.

It is an amenable number.

10114103141 is a deficient number, since it is larger than the sum of its proper divisors (389851).

10114103141 is an equidigital number, since it uses as much as digits as its factorization.

10114103141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 389850.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10114103141 its reverse (14130141101), we get a palindrome (24244244242).

The spelling of 10114103141 in words is "ten billion, one hundred fourteen million, one hundred three thousand, one hundred forty-one".

Divisors: 1 27947 361903 10114103141