Base | Representation |
---|---|
bin | 11101011011111001101… |
… | …11110111011011110111 |
3 | 10120200122001202002002012 |
4 | 32231330313313123313 |
5 | 113032333024144302 |
6 | 2052345244234435 |
7 | 133033511664533 |
oct | 16557467673367 |
9 | 3520561662065 |
10 | 1011412334327 |
11 | 35aa3499365a |
12 | 144027b3ba1b |
13 | 744b67629a5 |
14 | 36d49dacbc3 |
15 | 1b498603a52 |
hex | eb7cdf76f7 |
1011412334327 has 2 divisors, whose sum is σ = 1011412334328. Its totient is φ = 1011412334326.
The previous prime is 1011412334297. The next prime is 1011412334329. The reversal of 1011412334327 is 7234332141101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011412334327 - 214 = 1011412317943 is a prime.
Together with 1011412334329, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011412334293 and 1011412334302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011412334329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505706167163 + 505706167164.
It is an arithmetic number, because the mean of its divisors is an integer number (505706167164).
Almost surely, 21011412334327 is an apocalyptic number.
1011412334327 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011412334327 is an equidigital number, since it uses as much as digits as its factorization.
1011412334327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 1011412334327 its reverse (7234332141101), we get a palindrome (8245744475428).
The spelling of 1011412334327 in words is "one trillion, eleven billion, four hundred twelve million, three hundred thirty-four thousand, three hundred twenty-seven".
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