10114220143 has 4 divisors (see below), whose sum is σ = 10165561560. Its totient is φ = 10062878728.

The previous prime is 10114220113. The next prime is 10114220191. The reversal of 10114220143 is 34102241101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10114220143 - 2²⁹ = 9577349231 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10114220143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10114220113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25670413 + ... + 25670806.

It is an arithmetic number, because the mean of its divisors is an integer number (2541390390).

Almost surely, 2^10114220143 is an apocalyptic number.

10114220143 is a deficient number, since it is larger than the sum of its proper divisors (51341417).

10114220143 is an equidigital number, since it uses as much as digits as its factorization.

10114220143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51341416.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 10114220143 its reverse (34102241101), we get a palindrome (44216461244).

The spelling of 10114220143 in words is "ten billion, one hundred fourteen million, two hundred twenty thousand, one hundred forty-three".