10115031314551 has 2 divisors, whose sum is σ = 10115031314552. Its totient is φ = 10115031314550.

The previous prime is 10115031314471. The next prime is 10115031314567. The reversal of 10115031314551 is 15541313051101.

10115031314551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10115031314551 - 2¹⁵ = 10115031281783 is a prime.

It is a super-2 number, since 2×10115031314551² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10115031314581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057515657275 + 5057515657276.

It is an arithmetic number, because the mean of its divisors is an integer number (5057515657276).

Almost surely, 2^{10115031314551} is an apocalyptic number.

10115031314551 is a deficient number, since it is larger than the sum of its proper divisors (1).

10115031314551 is an equidigital number, since it uses as much as digits as its factorization.

10115031314551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4500, while the sum is 31.

Adding to 10115031314551 its reverse (15541313051101), we get a palindrome (25656344365652).

The spelling of 10115031314551 in words is "ten trillion, one hundred fifteen billion, thirty-one million, three hundred fourteen thousand, five hundred fifty-one".