1011712433 has 4 divisors (see below), whose sum is σ = 1036388388. Its totient is φ = 987036480.

The previous prime is 1011712417. The next prime is 1011712439. The reversal of 1011712433 is 3342171101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88585744 + 923126689 = 9412^2 + 30383^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011712433 - 2⁴ = 1011712417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011712399 and 1011712408.

It is not an unprimeable number, because it can be changed into a prime (1011712439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12337916 + ... + 12337997.

It is an arithmetic number, because the mean of its divisors is an integer number (259097097).

Almost surely, 2^1011712433 is an apocalyptic number.

It is an amenable number.

1011712433 is a deficient number, since it is larger than the sum of its proper divisors (24675955).

1011712433 is an equidigital number, since it uses as much as digits as its factorization.

1011712433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24675954.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 1011712433 is about 31807.4273244474. The cubic root of 1011712433 is about 1003.8890004030.

Adding to 1011712433 its reverse (3342171101), we get a palindrome (4353883534).

The spelling of 1011712433 in words is "one billion, eleven million, seven hundred twelve thousand, four hundred thirty-three".