101200051115 has 8 divisors (see below), whose sum is σ = 125627649840. Its totient is φ = 78168315232.

The previous prime is 101200051109. The next prime is 101200051157. The reversal of 101200051115 is 511150002101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101200051115 - 2¹⁴ = 101200034731 is a prime.

It is a super-2 number, since 2×101200051115² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101200051093 and 101200051102.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348965549 + ... + 348965838.

It is an arithmetic number, because the mean of its divisors is an integer number (15703456230).

Almost surely, 2^101200051115 is an apocalyptic number.

101200051115 is a deficient number, since it is larger than the sum of its proper divisors (24427598725).

101200051115 is an equidigital number, since it uses as much as digits as its factorization.

101200051115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 697931421.

The product of its (nonzero) digits is 50, while the sum is 17.

Adding to 101200051115 its reverse (511150002101), we get a palindrome (612350053216).

The spelling of 101200051115 in words is "one hundred one billion, two hundred million, fifty-one thousand, one hundred fifteen".