1012003001113 has 8 divisors (see below), whose sum is σ = 1107715770056. Its totient is φ = 918842572800.

The previous prime is 1012003001099. The next prime is 1012003001143. The reversal of 1012003001113 is 3111003002101.

It can be written as a sum of positive squares in 4 ways, for example, as 88430106384 + 923572894729 = 297372^2 + 961027^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1012003001113 - 2²¹ = 1012000903961 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012003001093 and 1012003001102.

It is not an unprimeable number, because it can be changed into a prime (1012003001143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 638084328 + ... + 638085913.

It is an arithmetic number, because the mean of its divisors is an integer number (138464471257).

Almost surely, 2^{1012003001113} is an apocalyptic number.

1012003001113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1012003001113 is a deficient number, since it is larger than the sum of its proper divisors (95712768943).

1012003001113 is a wasteful number, since it uses less digits than its factorization.

1012003001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1276170315.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1012003001113 its reverse (3111003002101), we get a palindrome (4123006003214).

The spelling of 1012003001113 in words is "one trillion, twelve billion, three million, one thousand, one hundred thirteen".