Base | Representation |
---|---|
bin | 10010110110011010… |
… | …00111100100110011 |
3 | 222010021202100112222 |
4 | 21123031013210303 |
5 | 131211221201042 |
6 | 4352112511255 |
7 | 505533301103 |
oct | 113315074463 |
9 | 28107670488 |
10 | 10120100147 |
11 | 4323595033 |
12 | 1b6524b52b |
13 | c5384ab51 |
14 | 6c00a7203 |
15 | 3e36d32d2 |
hex | 25b347933 |
10120100147 has 2 divisors, whose sum is σ = 10120100148. Its totient is φ = 10120100146.
The previous prime is 10120100099. The next prime is 10120100149. The reversal of 10120100147 is 74100102101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10120100147 - 26 = 10120100083 is a prime.
It is a super-3 number, since 3×101201001473 (a number of 31 digits) contains 333 as substring.
Together with 10120100149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10120100149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060050073 + 5060050074.
It is an arithmetic number, because the mean of its divisors is an integer number (5060050074).
Almost surely, 210120100147 is an apocalyptic number.
10120100147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120100147 is an equidigital number, since it uses as much as digits as its factorization.
10120100147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 10120100147 its reverse (74100102101), we get a palindrome (84220202248).
The spelling of 10120100147 in words is "ten billion, one hundred twenty million, one hundred thousand, one hundred forty-seven".
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