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1012011113 = 26328313597
BaseRepresentation
bin111100010100100…
…001000001101001
32121112021111021002
4330110201001221
54033033323423
6244230524345
734035644501
oct7424410151
92545244232
101012011113
1147a287a23
12242b066b5
13131884259
1498596a01
155dca5228
hex3c521069

1012011113 has 8 divisors (see below), whose sum is σ = 1019523648. Its totient is φ = 1004526864.

The previous prime is 1012011107. The next prime is 1012011157. The reversal of 1012011113 is 3111102101.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1012011113 - 210 = 1012010089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012011094 and 1012011103.

It is not an unprimeable number, because it can be changed into a prime (1012011313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67631 + ... + 81227.

It is an arithmetic number, because the mean of its divisors is an integer number (127440456).

Almost surely, 21012011113 is an apocalyptic number.

It is an amenable number.

1012011113 is a deficient number, since it is larger than the sum of its proper divisors (7512535).

1012011113 is a wasteful number, since it uses less digits than its factorization.

1012011113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14143.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 1012011113 is about 31812.1221077752. The cubic root of 1012011113 is about 1003.9877807992.

Adding to 1012011113 its reverse (3111102101), we get a palindrome (4123113214).

The spelling of 1012011113 in words is "one billion, twelve million, eleven thousand, one hundred thirteen".

Divisors: 1 263 283 13597 74429 3576011 3847951 1012011113