Base | Representation |
---|---|
bin | 10010110110011010… |
… | …01010011110000011 |
3 | 222010021202221211002 |
4 | 21123031022132003 |
5 | 131211222041003 |
6 | 4352113042215 |
7 | 505533350501 |
oct | 113315123603 |
9 | 28107687732 |
10 | 10120112003 |
11 | 43235a2a31 |
12 | 1b6525636b |
13 | c53853371 |
14 | 6c00ab671 |
15 | 3e36d6a88 |
hex | 25b34a783 |
10120112003 has 2 divisors, whose sum is σ = 10120112004. Its totient is φ = 10120112002.
The previous prime is 10120111999. The next prime is 10120112011. The reversal of 10120112003 is 30021102101.
10120112003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10120112003 - 22 = 10120111999 is a prime.
It is not a weakly prime, because it can be changed into another prime (10120112603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060056001 + 5060056002.
It is an arithmetic number, because the mean of its divisors is an integer number (5060056002).
Almost surely, 210120112003 is an apocalyptic number.
10120112003 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120112003 is an equidigital number, since it uses as much as digits as its factorization.
10120112003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 10120112003 its reverse (30021102101), we get a palindrome (40141214104).
The spelling of 10120112003 in words is "ten billion, one hundred twenty million, one hundred twelve thousand, three".
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